[Metafacture] how to define a filter, where the selected value is in a deeper level than the filter criterias

[Thomas Gängler]

Hi all,

we would like to create a filter with metamorph where the selected 
values are located in a deeper level than the filter criterias:

1. we have a kind of mabxml, excerpt:

<?xml version="1.0" encoding="utf-8"?>
<OAI-PMH xmlns="http://www.openarchives.org/OAI/2.0/" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://www.openarchives.org/OAI/2.0/ 
http://www.openarchives.org/OAI/2.0/OAI-PMH.xsd">
<ListRecords>
   <record>
    <header>
     <identifier>libero-publish:13703983</identifier>
    </header>
    <metadata>
     <record xmlns="http://www.ddb.de/professionell/mabxml/mabxml-1.xsd">
      <leader>00946nM2.01200024||||||h</leader>
      <controlfield tag="LDR">00946nM2.01200024||||||h</controlfield>
      <controlfield tag="SYS">13703983</controlfield>
     <datafield tag="000" ind1="" ind2="">
       <subfield code="a">13703983</subfield>
     </datafield>

     ...

     <datafield tag="088" ind1="a" ind2="">
       <subfield 
code="a">http://digitool.hbz-nrw.de:1801/webclient/DeliveryManager?pid=3597032</subfield>
     </datafield>

     ...

    </record>
   </metadata>
  </record>
</ListRecords>
</OAI-PMH>


2. with a filter statement we can access values for specific mab keys, 
e.g., 088a (note a pre-processing-step in our workflow is the RDFization 
of the data source (that's why the uris and rdf:value properties))

<?xml version="1.1" encoding="UTF-8" standalone="no"?>
<metamorph xmlns="http://www.culturegraph.org/metamorph"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" entityMarker="&#30;"
	version="1" xsi:schemaLocation="http://www.culturegraph.org/metamorph 
metamorph.xsd">
	<meta>
		<name>mapping1</name>
	</meta>
	<rules>
		<combine name="ok" value="${out}" sameEntity="true" reset="false">
			
			<!-- filter elements -->
			<data
			 
source="http://www.openarchives.org/OAI/2.0/metadata&#30;http://www.ddb.de/professionell/mabxml/mabxml-1.xsd#record&#30;http://www.ddb.de/professionell/mabxml/mabxml-1.xsd#datafield&#30;http://www.ddb.de/professionell/mabxml/mabxml-1.xsd#tag">
				<equals string="088" />
			</data>
			<data
			 
source="http://www.openarchives.org/OAI/2.0/metadata&#30;http://www.ddb.de/professionell/mabxml/mabxml-1.xsd#record&#30;http://www.ddb.de/professionell/mabxml/mabxml-1.xsd#datafield&#30;http://www.ddb.de/professionell/mabxml/mabxml-1.xsd#ind1">
				<equals string="a" />
			</data>

			<!-- value of attribute path that should be selected for further 
processing -->
			<data name="out"
			 
source="http://www.openarchives.org/OAI/2.0/metadata&#30;http://www.ddb.de/professionell/mabxml/mabxml-1.xsd#record&#30;http://www.ddb.de/professionell/mabxml/mabxml-1.xsd#datafield&#30;http://www.ddb.de/professionell/mabxml/mabxml-1.xsd#subfield&#30;http://www.w3.org/1999/02/22-rdf-syntax-ns#value" 
/>

		</combine>
	</rules>
</metamorph>


==> to simplify these filter statements we can make use of prefixes for 
example (to shorten the attributes of the attribute paths (keys of the 
key/value pairs)):

- 1. filter statement: 
oai:metadata/mabxml:record/mabxml:datafield/mabxml:tag = "088"
- 2. filter statement: 
oai:metadata/mabxml:record/mabxml:datafield/mabxml:ind1 = "a"

==> the value that should be selected is located one level deeper than 
the filter statements: 
oai:metadata/mabxml:record/mabxml:datafield/mabxml:subfield/rdf:value

====> our tests results are so far that we cannot select values from 
deeper level in a a hierarchy than the filter statements (i.e., we can 
select, e.g., oai:metadata/mabxml:record/mabxml:datafield/mabxml:ind2, 
which is at the same level as the filter statements)

 From our knowledge and understanding of Metafacture we know that the 
value that we would like to select is in another entity (because it is 
located in a deeper hierarchy in the record). So our question is now: Is 
Metafacture able to handle filters that make use of attribute paths 
across the whole hierarchy of a record?

Thanks a lot in advance for all your help.

Cheers,


Thomas